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IBM A2090-730 Exam Syllabus Topics:

IBM Assessment: DB2 9 Family Fundamentals Sample Questions:

Question 1

Which of the following DB2 objects are publicly referenced names that require no special authority or privilege to use them?

A. View
B. Package
C. Table
D. Alias

Question 2

Which of the following statements will catalog the database MYDB on the node MYNODE and assign it the alias MYNEWDB?

A. CATALOG DATABASEmynewdb AT NODE mynode
B. CATALOG DATABASEmydb AT NODE mynode
C. CATALOG DATABASEmynewdb AS mydb AT NODE mynode
D. CATALOG DATABASEmydb AS mynewdb AT NODE mynode

Question 3

If the following SQL statements are executed:
CREATE TABLE tab1 (id SMALLINT NOT NULL PRIMARY KEY,
name VARCHAR(25));
CREATE TABLE tab2 (empid SMALLINT,
weekno SMALLINT,
payamt DECIMAL(6,2),
CONSTRAINT const1 FOREIGN KEY (empid)
REFERENCES taba(id) ON UPDATE NO ACTION);
Which of the following statements is true?

A. When values that exist in the ID column of table TAB1 are updated, corresponding values in the EMPID column of table TAB2 are updated as well
B. The updating of values in the ID column of table TAB1 is not allowed
C. Only values that do not already exist in the ID column of table TAB1 are allowed to be inserted in the EMPID column of table TAB2
D. Only values that exist in the ID column of table TAB1 are allowed to be inserted in the EMPID column of table TAB2

Question 4

Which of the following strings can NOT be inserted into an XML column using XMLPARSE()?

A. "<?xml version='1.0' encoding='UTF-8' ?>"
B. "<name>John Doe</name>"
C. "<p></p>"
D. "<employee />"

Question 5

Which of the following is NOT a difference between a unique index and a primary key?

A. A primary key is a special form of a unique constraint; both use a unique index.
B. Unique indexes can be defined over one or more columns that allow null values; primary keys cannot contain null values.
C. A table can have many unique indexes but only one primary key.
D. Unique indexes can be defined over one or more columns; primary keys can only be defined on a single column.

Solutions: